(x^3y^-1z^-5)^-2/(x^5y^4z^2)^5

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Solution for (x^3y^-1z^-5)^-2/(x^5y^4z^2)^5 equation: 


D( x )

(x^5*y^4*z^2)^5 = 0

x^3*y^-1*z^-5 = 0

(x^5*y^4*z^2)^5 = 0

(x^5*y^4*z^2)^5 = 0

x^25*y^20*z^10 = 0 // : y^20*z^10

x^25 = 0

x = 0

x^3*y^-1*z^-5 = 0

x^3*y^-1*z^-5 = 0

x^3*y^-1*z^-5 = 0 // : y^-1*z^-5

x^3 = 0

x = 0

x in (-oo:0) U (0:+oo)

((x^3*y^-1*z^-5)^-2)/((x^5*y^4*z^2)^5) = 0

x^-31*y^-18 = 0 // : y^-18

x^-31 = 0

x naleu017Cy do O

x belongs to the empty set

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